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Excess of `PCl_(5)` reacts with concentrated `H_(2)SO_(4)` giving :A. chlorosulphonic acidB. thionyl chlorideC. sulphuryl chlorideD. sulphurous acid |
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Answer» Correct Answer - C `PCl_(5)` reacts with conc. `H_2SO_4` to give sulphuryl chloride by replacing its hydroxyl groups with chlorine atoms. `underset(or H_(2)SO_(4)" Sulphuric acid ")(SO_(2)(OH)_(2))+2PCl_(5) to underset("Sulphuryl chloride ")(SO_(2)Cl_(2))+2POCl_(3)+2HCl ` |
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