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Excess pressure inside one soap bubble is four times that of other. Then the ratio of volume of first bubble to second one isA. `1:64`B. `1:4`C. `64:1`D. `1:2`

Answer» Correct Answer - A
`(4S)/(R_(1))=4((4S)/(R_(2)))`
`impliesR_(2)=4R_(1)`
Required ratio `=((4)/(3)piR_(1)^(3))/((4)/(3)piR_(2)^(3))`


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