1.

Excitation energy of a hydrogen like ion in its first excitation state is 40.8 eV. Energy needed to remove the electron from the ion in gruond state isA. 54.4 eVB. 13.6 eVC. 40.8 eVD. 27.2 eV

Answer» Correct Answer - A
Excitation energy , `DeltaE =E_(2)-E_(1)=13.6 [(1)/(1^(2))-(1)/(2^(2))]`
`" " 40.8=13.6 Z^(2)xx(3)/(4)`
`:. " " Z=2`
So, required energy to remove the electron from gound state `=+(13.6Z^(2))/((1)^(2))=13.6(2)^(2)=54.4 eV`


Discussion

No Comment Found

Related InterviewSolutions