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EXERCISE 3.10lculate the size of the unknown angles in these polygons.Give reasons for your answers.10070°(110°

Answer»

a = 115° + 100° + 70° + a = 360° a = 275°- 360°a = 85°

115°+100°+70°+a=360°275°+a = 360°a=360°-275°a=85°

sum of this figure is 360 ,115+100+70+a=360 ,a =360-275 ,a =275

the total no. of sum of angles in a polygon is 360.

115+100+70+X= 360X= 85.

a+115°+70°+100°=360° ( A.S.P of parallelogram)a+285°=360°a=360°- 285°a=75°

115+100+70+a=360285+a=360a=360-285a=75



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