Exercises 1. An athlete completes one round of a circular track of diameter200 m in 40 s. What will be the distance covered and thedisplacement at the end of 2 minutes 20 s?

Exercises 1. An athlete completes one round of a circular track of d

1.	Exercises 1. An athlete completes one round of a circular track of diameter200 m in 40 s. What will be the distance covered and thedisplacement at the end of 2 minutes 20 s?
Answer» Given thatGiven thatDiameter of circular track = 200 mGiven thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mGiven thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.Given thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findGiven thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Given thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Given thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be USED :-Given thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeGiven thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeCircumference of circle = 2πrGiven thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeCircumference of circle = 2πrSolution :-Given thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeCircumference of circle = 2πrSolution :-2 min 20 seconds = 140 secondsGiven thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeCircumference of circle = 2πrSolution :-2 min 20 seconds = 140 secondsNumber of rounds = 140/4 = 35Given thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeCircumference of circle = 2πrSolution :-2 min 20 seconds = 140 secondsNumber of rounds = 140/4 = 35= Distance covered = 35 × circumferenceGiven thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeCircumference of circle = 2πrSolution :-2 min 20 seconds = 140 secondsNumber of rounds = 140/4 = 35= Distance covered = 35 × circumference= Distance covered = 35 × 2 × 22/7 × 100Given thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeCircumference of circle = 2πrSolution :-2 min 20 seconds = 140 secondsNumber of rounds = 140/4 = 35= Distance covered = 35 × circumference= Distance covered = 35 × 2 × 22/7 × 100= Distance covered = 5 × 2 × 22 × 100Given thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeCircumference of circle = 2πrSolution :-2 min 20 seconds = 140 secondsNumber of rounds = 140/4 = 35= Distance covered = 35 × circumference= Distance covered = 35 × 2 × 22/7 × 100= Distance covered = 5 × 2 × 22 × 100= Distance covered = 22000 mGiven thatDiameter of circular track = 200 mRadius, r = 200/2 = 100 mTime is taken by an athlete to complete one round = 40 seconds.We have to findDistance covered = ??Displacement = ??Formula to be used :-Speed = Distance/TimeCircumference of circle = 2πrSolution :-2 min 20 seconds = 140 secondsNumber of rounds = 140/4 = 35= Distance covered = 35 × circumference= Distance covered = 35 × 2 × 22/7 × 100= Distance covered = 5 × 2 × 22 × 100= Distance covered = 22000 mHence, the distance covered at the end of 2 min 20 seconds is 22000 m or 22 km.Explanation:Mark me as the brainliest..

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Exercises 1. An athlete completes one round of a circular track of diameter200 m in 40 s. What will be the distance covered and thedisplacement at the end of 2 minutes 20 s?​

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Exercises 1. An athlete completes one round of a circular track of diameter200 m in 40 s. What will be the distance covered and thedisplacement at the end of 2 minutes 20 s?