

InterviewSolution
Saved Bookmarks
1. |
Experiment shows that Nickel oxide has the formula Ni096 O1.00 . What fraction of Nickel exists as of Ni2+ and Ni3+ ions ? |
Answer» Let the number of Ni2+ . Then the number of Ni3+ ion will be = (0.96 – x). Total number of cation, = 2 x + 3 (0.96 – x) = 2x + 2.88 – 3x = ( – x) + 2.88 Number of anions O2- ( – 2) x 1 = -2. Number of cations = Number of anions – x + 2.88 2 – x = – 2.88 + 2 x = 0.88 % of Ni as Ni2 = \(\frac{0.08}{0.96}\times 100\) = 91.66% Number of Ni3+ ion will be = 0.96 – x = 0.96 – 0.88 = 0.08 % of Ni as Ni3+ = \(\frac{0.08}{0.96}\times 100\) = 8.3 % |
|