Experimentally it was found that a metal oxide has formulaM_(0.98)O. Metal M is present asM^(2+) and M^(3+) in iyts oxide. Fraction of the metal which exists asM^(3+)would be

Experimentally it was found that a metal oxide has formulaM_(0.98)O. M

1.	Experimentally it was found that a metal oxide has formulaM_(0.98)O. Metal M is present asM^(2+) and M^(3+) in iyts oxide. Fraction of the metal which exists asM^(3+)would be
Answer» 0.0508 0.0701 0.0408 0.0605 Solution :The formula ` M_(0.98)O` shows that if there were 200 O-ATOMS present as ` O^(2-)` IONS, then there98 M atoms present as ` M^(2+) and M^(3+)` . Suppose`M^(3+) =X "then" M^(2+) = 98-x`. As the compound as a whole is netural . total charge on `M^(3+) and M^(2+)`= Total charge on ` 100 O^(2-) ` ions x (+3)+ ( 98-x) (+2) = 100 `xx`2 or 3 x + 19 6- 2 x = 200 or x = 4 % of ` M^(3+) = 4/98 xx 100 = 4.08 %`