Experimentally it was found that a metal oxide has formula M_(0.98)O. Metal M ispresented as M^(2+) and M^(3+) in its oxide. Fraction of the metal which exists as M^(3+) would be

Experimentally it was found that a metal oxide has formula M_(0.98)O.

1.	Experimentally it was found that a metal oxide has formula M_(0.98)O. Metal M ispresented as M^(2+) and M^(3+) in its oxide. Fraction of the metal which exists as M^(3+) would be
Answer» `5.08%` `7.01%` `4.08%` `6.05%` Solution :The FORMULA `M_(0.98)O` shows that if there were 100 O atoms present as `O^(2-)`ions, than 98 M atoms will be present as `M^(2+) and M^(3+)`. Suppose `M^(3+)`= x then `M^(2+)`=98-x. As the compound as a WHOLE is NEUTRAL , the total CHARGE on `M^(3+) and M^(2+)` = totalcharge on 100 `O^(2-) ion` `x(+3)times(98-x)TIMES2=(100)times2` `3x+196-2x=200therefore x=2` `therefore % "of "M^(3+)=4/98times100=4.08%`