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Explain 3 newton law from calculas method |
| Answer» First law of newtona=dv/dtadt=dvDifferenciating both sidea[t]^t1-t2=[v]^v-ua[t-0]=[v-u]at=v-uV=u+atSecond law of newton v=dx/dt. [v=u+at]u+at=dx/dtudt+atdt=dxDifferenciating both sideu[t]^t-0+a[t^2]^t-0=[x]^x-0u[t-0]+a[t^2-0/2]=[x-0]ut+1/2at^2=x. Wherex=displacementx=ut+1/2at^2 | |