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Explain common ion effect taking place in CH_(3)COOH+CH_(3)COONaandNH_(4)OH+NH_(4)Cl. |
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Answer» Solution :(a) `CH_(3)COOHhArrCH_(3)COO^(-)+H^(+)` `CH_(3)COONatoCH_(3)COO^(-)+NA^(+)` Dissociation of acetic acid can be suppressed by adding a strong electrolyte `CH_(3)COONa` containing common ion `CH_(3)COO^(-)`. (B) `NH_(4)OHhArrNH_(4)^(+)+OH^(-)` `NH_(4)CL toNH_(4)^(+)+Cl^(-)` Dissociation of `NH_(4)OH` is suppressed by adding a strong electrolyte `NH_(4)Cl` containing `NH_(4)^(+)` ion as common ion. |
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