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Explain concentration of HA, CH_3COO^(-) , H^(+),Na^(+) when 0.05 M sodium acetate is added in 0.05 M acetic acid. |
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Answer» Solution :`{:(CH_3COOH hArr , CH_3COO^(-)+,H^(+)),((0.05-x)M,x M, x M),(CH_3COONa to , CH_3COO^(-) + , Na^+),((0.05),0.05 M,0.05 M):}` Thus, in MIX solution `[CH_3COOH]`=INITIAL concentration is 0.05 M is less equal to x `x lt lt 0.05 [CH_3COOH] APPROX` 0.05 in solution `CH_3COO^(-)`=0.05 + x`approx` 0.05 M in solution `[H^+]`= x M and `[Na^+]`=0.05 M Due to common ion effect of `CH_3COO^-` ionization of `CH_3COOH` is less, `[H^+]`=x decrease and pH INCREASE . `[CH_3COO^-]` increase than pH increase. |
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