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Explain : Enthalpy : state function.ORDelta H= q_(p) Or Prove : "The change in enthalpy of the system in which chemical reaction occurs is equal to value of heat gain by system."

Answer»

SOLUTION :`Delta U= q+w` we may WRITE as
`Delta U = q_(p) - pDelta V` at constant pressure,
where `q_(p)=` heat absorbed by system
`pDelta V=` expansion work done by system
When heat is absorbed at constant pressure by system, internal energy turns form `U_(1)` to `U_(2)` and volume turns `V_(1)` to` V_(2)`.
`therefore Delta U= U_(2) - U_(1)`
`Delta V= V_(2) - V_(1)`
Put this value in above equation.
`therefore U_(2) - U_(1) = q_(p) - p (V_(2) - V_(1) )`
`q_(p) = (U_(2) - U_(1) ) + P (V_(2) - V_(1) )`
`q_p = (U_(2) + pV_(2)) - (U_(1) + pV_(1) ) ""...(i)`
here, `U+pV` is a state function. It is mentioned as H
`H= U+ pV""...(ii)`
`therefore q_(p) = H_(2) - H_(1) = Delta H`
H is a state function, because, U, p, V are state functions, for fixed change at constant pressure,
`Delta H = Delta U + pDelta V ""...(iii)`
`Delta H` is positive for endothermic reactions which ABSORB heat from the surroundings and `Delta H` is NEGATIVE for exothermic reactions which evolve heat during the reaction.


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