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Explain free expansion. |
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Answer» <P> Solution :EXPANSION of a gas in vacuum `(p_(ex) = 0)` is called free expansion. No work is done during free expansion of an ideal gas whether the process is reversible or irreversible.Now, we can write equation-(i) in number of ways depending on the type of processes. Let us substitute `W=- p_(ex) Delta V` in equation-(i), and we get `Delta U= q-p_(ex) Delta U "where",(w=p_(ex) Delta V)` If a process is CARRIED out at constant volume `(Delta V= 0)`, then `Delta U= q_(V)` The subscript V in `q_(V)` denotes that heat is supplied at constant volume. |
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