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Explain kinetic energy and average translation kinetic and average square speed. |
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Answer» Solution :KINETIC energy : Kinetic energy of molecule is represent as follow. Kinetic energy `=(1)/(2)mu^(2) ""` ……(Eq. -i) Average translation kinetic energy : `(1)/(2)m u^(2)`is known as translation kinetic energy. where,`bar(u)^(2)=`Average SPEED of root of all molecules in molecules in MOTION in straight line. Average square speed `(bar(u)^(2))` : Average square speed is measurement of average kinetic speed of gaseous molecules. If VELOCITY of n molecules are`u_(1), u_(2), u_(3)`, .... than its quare `u_(1)^(2), u_(2)^(2), u_(3)^(2), ...... u_(n)^(2)` so, `bar(u)^(2)=(u_(1)^(2)+u_(2)^(2)+u_(3)^(2).....u_(n)^(2))/(n)` `bar(u)^(2)=(u_(RMS))^(2)=(3RT)/(M)` |
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