1.

Explain(n +1)rulesfor energyof orbital byexample .

Answer»

Solution :Energyof electronin orbitalis BASEDON valueofn and L
Rule1 : The orbitalwhichhas lowvalueof(N+1)hasless ENERGY
Rule -2: if twoorbitalshavesame(n+1)thanthe orbitalwhichhas less valueof n haslessenergy
e.g.Energyof 3porbitalis lessthan 4p
for4s :n=4l =0(n+ l)= (4+0) =4
Energyof `4sgt 3P`


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