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| 1. |
Explain olelic acid experiment |
| Answer» 1cc of oleic acid is dissolved in 20cc alcohol.1cc of this solution is again dissolved in 20cc alcohol. now the concentration of oleic acid in 1cc of this solution is 1/20x20. \'n\' drop of this solution is poured on surface of water(in a tray) of area \'a\' and \'t\' is the thickness of solution on surface of water. the alcohol having low boiling point evaporates quickly and oleic acid is left on surface of water. now, if \'v\' is volume of 1 drop of solution then volume of \'n\' drops of solution is \'nv\' and volume of oleic acid in \'n\' drop is nv/20x20.(eq.1) volume of solution on surface of water is \'a x t\'(eq.2) . From eq1&2 , a x t = nv/20x20 .or t=nv/20 x 20 x a. | |