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Explain : 'Sodium carbonate solution is basic.' |
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Answer» Solution :It is a SALT of strong base NaOH and weak ACID `H_2CO_3` therefore solution BECOME basic. `Na_2CO_3 to 2Na^(+) +CO_3^(2-)` `NA^+` is not hydrolyses `CO_3^(2-)` is hydrated `CO_3^(2-) + 2H_2O hArr H_2CO_3 + 2OH^(-)` Here, `[OH^-]` INCREASES so solution is basic. |
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