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Explain sp^(2) hybridisation in BF_(3). |
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Answer» <P> Solution :`sp^(2)` hybridisation in boron trifluoride: Boron atom B:Electronic configuration `[H_(2)]2s^(2)p^(1).`  (II) In boron, the s orbital and two p orbitals in the valence shell hybridises to generate THREE equivalent `sp^(2)` orbitals. These 3 orbitals LIE in the same y plane and the angle between any two orbitals is equal to `120^(@)` (iii) The 3 `sp^(2)` hybridised orbitals of boron now overlap with the `2p_(z)` orbitals of fluorine (3 atoms) This overlap takes place along the axis. 
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