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Explain sp^(3)d^(2) hybridization SF_(6) molecule. |
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Answer» Solution :Sulphur hexafluoride has one sulphur and six fluorine atoms, Sulphur atoms has six unpaired electrons in the excited state. S (ground state) `: [Ne] 3s^(1) 3p_(x)^(1), 3p_(x)^(1), 3p_(y)^(1), 3d_(xy)^(1), 3d_(xy)^(1)`  During the formation `SF_(6), 3s` three 3p and two 3d orbitals mix to form `sp^(3)d^(2)` HYDRID orbital. Thesehybrid orbitals are oriented towares six corners of an octahedron.  The six hybrid ortbihals of sulphur overlpa with six `2p_(x)` orbitals fluorine to form six-covalent bonds. HENCE the molecule of `SF_(6)` octahedral STRUCTURE. |
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