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Explain the action of alcoholic potash with bromoethane. |
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Answer» Solution :ELIMINATION reaction TAKES place when alcoholie potash reacts with bromoethane: `underset("BROMO ethane") (CH_(3) - CH_(2)Br + overset("Alcoholic")(KOH) to CH_(2) underset("Ethylene") (= CH_(2)) + KBR + H_(2) O` |
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