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Explain the bond formation in SF_(4)" and "C Cl_(4) using hybridisation concept. SF_(4) |
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Answer» Solution :`SF_(4)` : In `SF_(4)` the central atomis `sp^(3)` hybrisized . The molecule `SF_(4)` will have a total of 34 VALENCE electrons, 6 from sulfur atom will form 4 single with FLUORINE atoms. These bonds account for 8 electrons out of the `S_(4)` valence electrons. Each electron atom will have 3 lone pairs will use up 24 valence electrons. So total used valence electrons to 32. The remaining two electrons will be PLACED on the sulfur atom as a lone pair. Sulfur atom gets a total of 10 electrons , 8 from the bonds and 2 as lone pair . This is quite possible for sulfur because it has easy access to its 3d-orbitals, which means that it can expand its octet and accomodate more than 8 electrons. Sulful forms 4 single bonds and has 1 lone pair, which means that its steric number is equal to 5 . In this case, sulfur will use five hybrid orbitals, Such as one 3s orbital three 3P orbitals and one 3d orbital so the central atom is `SP^(3)` hybridised. 
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