InterviewSolution
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InterviewSolution
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Explain the determination of the internal resistance of a cell using voltmeter. |
Answer» Solution :Determination of internal RESISTANCE: The emf of cell `xi` is measured by connecting a high resistance voltmeter across it without connecting the external resistance R. Since the voltmeter draws verylittle current for DEFLECTION, the circuit may be considered as open. Hence, the voltmeter READING gives the emf of the cell. Then external resistance R is included in the circuit and current I is extablished in the circuit. The potential differenceacross R is equal to the potential difference across the cell (V).   The potential drop across the resistor R is `V=IR "" ...(1)` Due to internal resistance r of the cell, the voltmeter reads a value V, which is less than the emf of cell `xi`. It is because, CERTAIN amount of voltage (Ir) has dropped across the internal resistance r. Then`V=xi-Ir` `Ir=xi-V "" ...(2)` DIVIDING equation (2) by equation (1), we get `(Ir)/(IR)=(xi-V)/(V)` `r=|(xi-V)/(V)|R"" ...(3)` Since `xi, V and R` are known, internal resistance r can be determined. |
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