Explain the effect on value of Q_c by decrease the volume of CO_((g)) + 3H_(2(g)) hArr CH_(4(g)) + H_2O_((g))reaction vessel.

Explain the effect on value of Q_c by decrease the volume of CO_((g))

1.	Explain the effect on value of Q_c by decrease the volume of CO_((g)) + 3H_(2(g)) hArr CH_(4(g)) + H_2O_((g))reaction vessel.
Answer» Solution :If the VOLUME is decrease so pressure is increase and gaseous mol decrease (2 out of 4) therefore reaction is forward. To increase the pressure, the PARTIAL pressure of reactions `([CO] + [H_2])_((g))` increase and it is in DOMINATOR in the formuly of `Q_c` so `Q_c` decreases. `Q_c=([CH_4][H_2O])/([CO][H_2]^3) GT K`