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Explain the ionic bond formation in CaF_(2). |
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Answer» Solution :`CaF_(2)` , calcium fluoride : (i) Calcium , `CA : AR - 4s^(2)` Fluorine , `F - [He] 2s^(2) 2p^(5)` (ii) Calcium has two electrons in it valence shell and fluorine has seven electrons in its valence shell (iii) By losing two electrons , calcium attcium the INERT gas configuration of ARGON and dipositive cation `Ca^(2+)` (iv) Two fluorine atoms, each one electrons to become two uninegative fluoride ions `(F^(-))` there by attaining the stable configuration of Neon. (v) These three ions combine to form an ionic crystal in which they are helped together by electrostatic attractive force. (vi) During the formation of calcium fluoride crystal `1225.91" Kj mol"^(-1)` of ENERGY is released . This favours the formation of calcium fluoride, `CaF_(2)` and PtS stabilisation . |
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