A segmentation violation usually indicates an attempt to access memory which doesn't even exist. 

Segmentation violation usually OCCURS at the time of a program’s attempt for accessing memory location, which is not allowed to access. The following code should CREATE segmentation violation.

main() {

char *hello = “Hello WORLD”;

*hello = ‘h’;

}

At the time of compiling the program, the string “hello world” is placed in the BINARY mark of the program which is read-only marked. When loading, the compiler places the string along with other constants in the read-only SEGMENT of the memory. While executing a variable *hello is set to point the character ‘h’ , is attempted to write the character ‘h’ into the memory, which cause the segmentation violation. And, compiler does not check for assigning read only locations at compile time.

A segmentation violation usually indicates an attempt to access memory which doesn't even exist. 

Segmentation violation usually occurs at the time of a program’s attempt for accessing memory location, which is not allowed to access. The following code should create segmentation violation.

main() {

char *hello = “Hello World”;

*hello = ‘h’;

}

At the time of compiling the program, the string “hello world” is placed in the binary mark of the program which is read-only marked. When loading, the compiler places the string along with other constants in the read-only segment of the memory. While executing a variable *hello is set to point the character ‘h’ , is attempted to write the character ‘h’ into the memory, which cause the segmentation violation. And, compiler does not check for assigning read only locations at compile time.