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Explain the pressure and volume corrections in ideal gas equation? |
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Answer» At low temperature and high pressure intermolecular attractions cannot be neglected, the observed pressure P is smaller than the ideal pressure Pi. Therefore, Pi = P + p = P + an2/V2. As volume of gas molecules is not negligible as compared to total volume of the gas the ideal volume Vi is smaller than the observed volume. Therefore, Vi = V + v = V - nb. |
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