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Explain the relationship between free energy and equilibrium constant. |
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Answer» Solution :Let US consider a general equilibrium reaction `A+BhArrC+D` The free ENERGY change of the above reaction in any state `(DeltaG)` is related to the STRANDED free energy change of the `(DeltaG^(@))` according to following equation `DeltaG= DeltaG^(@)+RT "In " Q` where Q is reaction quotient . When equilibrium is attained , there is no further free energy change i.e. `DeltaG=0` and Q becomes equal to equilibrium constant. Hence the above equation becomes. `DeltaG^(@)=-RT "In"K_(eq)` This equation is KNOWN as Van 't Hofff equation `DeltaG^(@)=-2.303RTlogK_(eq)` We also know that `DeltaG^(@)=DeltaH^(@)-TDeltaS^(@)=-RT " In " K _(eq)` |
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