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Explain : The shape of H_(2)Ois V (angular). |
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Answer» Solution :The structure of `H_(2)O`is molecule can be EXPLAINED with the help of sps hybridization of oxygen and VSEPR theory. In `H_(2)O`the valence shell (outer) electronic configuration of oxygen in ground state is `2s^(2) 2p_(x)^(1) 2p_(y)^(1) 2p_(z)^(1)`having TWO paired electron and two half filled orbital. These four orbitals undergo `sp^(3)` hybridization in which two orbital are half filled & other two orbitals are completion filled. Two half filled `sp^(3)` orbital overlap with is orbital of H and form two O-H sigma bond. Two `sp^(3)` orbital are non bonding. As per VSEPR principle the repulsion between IONE pair is more than bonding pair. So due to this excess repulsion two O-H bond come closer so bond angle decrease from `104.5^(@)`to `104.5^(@)`. In this way `H_(2)`O has V shape & bond angle is `104.5^(@)` . 
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