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Explain the shape of I_(3)^(-) ion . |
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Answer» Solution :The CENTRAL I atom has the outer shell electronic configuration in the ground state as ` 5s^(2) 5p_(x)^(2) 5p_(y)^(2) p_(z)^(1) 5D^(0) ` . It undergoes` sp^(3)` d hydridisation . Out of the five ` sp^(3) d`hydrid ORBITALS , ONE in half-filled , one is empty and the remaining there are fully-filled . The half-filled froms covalent bond with iodine atom The empty orbital accepts electron pair from `I^(-)` ion to from a coordinate bond The remaining three fully-filled occupy equatorial positions. Thus , the geometry of three lone pairs and two bond pairs is TRIGONAL bipyramidal and the shape of `I_(3)^(-)` is linear as shown in the Fig . Similarly , the shapes of `ICl_(2)^(-) and [I Br F]^(-)` are also linear . 
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