1.

Explain the variation of ‘g’ with 1. height 2. depth

Answer»

Consider M to be mass of Earth and R to be radius of Earth. 

1. At a point ‘h’ above the ground

New g is gn = \(\frac {GM} {(R+h)^2}\)

= \(\frac {GM} {R^2[1+\frac{h}{R}]^2}\)

gn = g\([1+\frac {h}{R}]^{-2}\)

if h << R,

gn = g\([1-\frac {2h}{R}]\)

So, g decreases with increase in height,

2. At a depth ‘d’ below the ground. The new g, gd is given by

dd = g\([1-\frac {d}{R}]\)

So, g also decreases with depth.


Discussion

No Comment Found

Related InterviewSolutions