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Explain work energy theorem |
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Answer» W=½v²-½u² It states that the work done by an object is the change in kinetic energy of the body i.e. difference in final KE and inital KE.W=1/2mv^2-1/2mu^2W=1/2m(v^2-u^2)Hope you got the feel of the topic. Work done by a force on a body is equal to the change in the kinetic energy of the bodyLet us consider a body of mass M moving with the initial velocity u and when a constant force F is applied on it its velocity become Vdw=f×dxdw=m dv/dt × dxdw=mdv(dx/dt)dw=mvdvOn integrating|dw=|mvdvW=m |vdvW=m(v2)/2W=m(v2-u2)/2W=1/2mv2-1/2mu2 |
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