Saved Bookmarks
| 1. |
Explaind orbital . |
|
Answer» SOLUTION :d orbital: dorbitalexistin energyleveln=3,45…but in n=1 ,2 orbitald orbitalis notexistso 1AND2 dnotexist notof dorbitalsno of orbits = (2L + 1) for dorbitall=2so no of dorbitalsare five(5) sod subshellhas fiveorbitals No of d orbitals :fordorbitalsl=2and magneticquantumnumber`m_(1) = - 2 ,-1,0, +1` SHAPEOF d orbitals : fourdorbitalshave sameshapewithfourlobesSo`d_(xy)d_(yz)` and `d_(zx)`havelobesin theirxy, yz , zxplanewhichfor`d_(x)^(2) ` the lobesare on the x and yaxes. Shapeof `d_(x )`orbitalisdifferentformotherinwhichtwolobesaround2 axis .  Energyof d orbital : In anyonesubshelltheenergy of all fived orbitalsis sameandequivalenttheirshapeand sizealsosameit theprincipalquantumnumberincreaseandsizeand energyalsoincreaseandsizeenergyalsoincrease3d `lt 4d lt 5d` Radialnodeand ANGULARNODE : wherethe lobescombinethereelectrondensityis zero in dorbitalsangularnodeis l andradialnode is(n-1-1) for 3dorbitalnode(n-1) =3-2-1=0 Angularnode 1=2 For 3dorbitaltotalnodes=n- 1=3-1=2 nodes. |
|