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Express 1.3 2bar + 0.35bar in p/q.\(1.3\bar 2+0.\bar{35}\) |
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Answer» \(1.3\bar 2+0.\bar{35}\) = 1.322222...+ 0.353535... = 1.675757 = \(1.6\bar{75}\) Let x = \(1.6\bar{75}\) \(\therefore\) 10x = \(16.\bar{75}\) 1000 x = 1675.\(\bar{75}\) \(\therefore\) 1000 x - 10 x = 1675. \(\bar{75}\) - 16. \(\bar{75}\) ⇒ 990 x = 1659 ⇒ x = \(\frac{1659}{990}\) = \(\frac{553}{330}\) Hence, required p/q form is \(\frac{553}{330}\) |
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