1.

Express 1.3 2bar + 0.35bar in p/q.\(1.3\bar 2+0.\bar{35}\)

Answer»

\(1.3\bar 2+0.\bar{35}\) 

= 1.322222...+ 0.353535...

= 1.675757

\(1.6\bar{75}\)

Let x = \(1.6\bar{75}\)

\(\therefore\) 10x = \(16.\bar{75}\)

1000 x = 1675.\(\bar{75}\)

\(\therefore\) 1000 x - 10 x = 1675. \(\bar{75}\) - 16. \(\bar{75}\)

⇒ 990 x = 1659

⇒ x = \(\frac{1659}{990}\) = \(\frac{553}{330}\) 

Hence, required p/q form is \(\frac{553}{330}\)



Discussion

No Comment Found

Related InterviewSolutions