Express in standard form:A Helium atom has a diameter of 0.000000022 c

1.	Express in standard form:A Helium atom has a diameter of 0.000000022 cm.
Answer» Given that, The diameter of a helium atom = 0.000000022 cm Standard form = 0.22 × 10^-7 cm = 2.2 × 10^-1 × 10^-7 Using the law of exponent, a^m x aⁿ = a^m+n = 2.2 × 10^-1-7 = 2.2 × 10^-8 cm ∴ The standard form is 2.2 × 10^-8 cm

Express in standard form:A Helium atom has a diameter of 0.000000022 cm.

Answer»

Given that, The diameter of a helium atom = 0.000000022 cm

Standard form = 0.22 × 10^-7 cm

= 2.2 × 10^-1 × 10^-7

Using the law of exponent, a^m x aⁿ = a^m+n

= 2.2 × 10^-1-7

= 2.2 × 10^-8 cm

∴ The standard form is 2.2 × 10^-8 cm