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Express in the form ((I+i)^2)/(3-i) |
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Answer» SOLUTION : `((I+i)^2)/(3-i)=((1+i^2+2I)(3+i))/((3-i)(3+i))` `(2i(3+i))/(9-i^2)=(6I+2i^2)/(9+i)=(6i-2)/(10)` `(-2)/(10)+(6i)/(10)=- 1/5+(3I)/5` |
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