1.

Express linear equations in the form of ax + by + c = 0 and indicate the values of a, b and c in x/3 + y/4 = 7

Answer»

\(\frac x3 + \frac y4 = 7\)

\(\frac x3 + \frac y4 -7=0\)

 ⇒\(\frac {4x+3y-84}{12} = 0\)

⇒ 4x + 3y – 84 = 0 

Here a = 4, b = 3 and c = – 84



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