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Express linear equations in the form of ax + by + c = 0 and indicate the values of a, b and c in x/3 + y/4 = 7 |
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Answer» \(\frac x3 + \frac y4 = 7\) ⇒\(\frac x3 + \frac y4 -7=0\) ⇒\(\frac {4x+3y-84}{12} = 0\) ⇒ 4x + 3y – 84 = 0 Here a = 4, b = 3 and c = – 84 |
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