Express \(\tau_{yz}\) in terms of velocity gradients.(a) \(\tau_{yz}=μ(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})\)(b) \(\tau_{yz}=μ(\frac{\partial u}{\partial z}+\frac{\partial u}{\partial y})\)(c) \(\tau_{yz}=μ(\frac{\partial v}{\partial x}+\frac{\partial w}{\partial x})\)(d) \(\tau_{yz}=μ(\frac{\partial w}{\partial z}+\frac{\partial v}{\partial y})\)The question was asked during an online exam.I need to ask this question from Governing Equations topic in chapter Governing Equations of Fluid Dynamics of Computational Fluid Dynamics

Express \(\tau_{yz}\) in terms of velocity gradients.(a) \(\tau_{yz}=�

1.	Express \(\tau_{yz}\) in terms of velocity gradients.(a) \(\tau_{yz}=μ(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})\)(b) \(\tau_{yz}=μ(\frac{\partial u}{\partial z}+\frac{\partial u}{\partial y})\)(c) \(\tau_{yz}=μ(\frac{\partial v}{\partial x}+\frac{\partial w}{\partial x})\)(d) \(\tau_{yz}=μ(\frac{\partial w}{\partial z}+\frac{\partial v}{\partial y})\)The question was asked during an online exam.I need to ask this question from Governing Equations topic in chapter Governing Equations of Fluid Dynamics of Computational Fluid Dynamics
Answer» CORRECT OPTION is (a) \(\tau_{yz}=μ(\frac{\partial v}{\partial z}+\frac{\partial W}{\partial y})\) The EXPLANATION: For non-diagonal elements, \(\tau=\mu\left\{∇\vec{v}+(∇\vec{v})^T\right\}\) \(\tau_{yz}=\mu(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y})\).

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