InterviewSolution
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InterviewSolution
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`F_(2)` is a stronger oxidising agent than `Cl_(2)` |
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Answer» Correct Answer - The electrode potential of `F_(2)` and `Cl_(2)` are : `F_(2)+2e^(-)to2F^(-) ; E^(@)=+2.87 V` and `Cl_(2)+2e^(-)to2Cl^(-) ; E^(@)=1.36 V` Since `E^(@)` for `F_(2)//F^(-)` electrode is higher than of `Cl_(2)//Cl^(-)` electrode, therefore, `F_(2)` is more easily reduced than `Cl_(2)`.In other words, `F_(2)` is a stronger oxidising agent than `Cl_(2)`.For example, `F_(2)` oxidises `Cl^(-)` ions to `Cl_(2)` but `Cl_(2)` does not oxide `F^(-)` ions to `F_(2)`. `F_(2)+2Cl^(-)to2F^(-) + Cl_(2); Cl_(2) + 2F^(- -) ` |
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