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f(x) = {{:((1-coskx)/(x sinx), if x ne 0),(1/2, if x = 0):} at x= 0 |
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Answer» At `x=0, LHL = underset(hrarr0^(-))(lim)(1-coskx)/(xsinx)=underset(hrarr0)lim(1-cos(0-h))/((0-h)sin(0-h))` `= underset(hrarr0)(lim)(1-cos(-kh))/(-hsin(-h))` `= underset(hrarr0)(lim)(1-coskh)/(hsinh) ,[:' cos (-theta)=cos theta, sin(-theta)= - sin theta]` `= underset(hrarr0)lim(1-1+2SIN^(2)'(kh)/(2))/(hsinh), [:' cos theta = 1 - 2 sin^(2) ' (theta)/(2)]` `= underset(hrarr0)(lim) (2sin^(2)'(kh)/(2))/(h sinh)` `= underset(hrarr0)lim(2sin'(kh)/(2))/((kh)/(2)).(sin'(kh)/(2))/((kh)/(2)).(1)/((sinh)/(h)).(K^(2)h//4)/(h)` `= (2k^(2))/(4) = (k^(2))/(2)` , [`:' underset(hrarr0)(lim)' (sinh)/(h) = 1]` Also, `f(0) = 1/2 rArr(k^(2))/(2) = 1/2rArr k +- 1` |
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