1.

f(x)=⎧⎨⎩√1+px−√1−pxx:−1≤x<02x+1x−2:0≤x≤1 Is continuous in the interval [-1, 1], then p is equal to:

Answer» f(x)=1+px1pxx:1x<02x+1x2:0x1
Is continuous in the interval [-1, 1], then p is equal to:


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