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%f(x) = 3x2-x-ad f(1) = 4, dif(x) |
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Answer» f(x) = Integration of f'(x) = 3x³/3 +2*2/x² +c = x³+4/x² +c now putting f(1) = 4 , we get f(1) = 4 = (1)³+4/(1)²+c=> 4 = 5+c => c = 4-5 = -1 so, the function is f(x)= x³+4/x²-1 |
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