1.

f(x) = cot^(-1)x: R^(+) rarr (0,pi) and g(x) = 2x-x^(2): R rarrR then the range of f(g(x)) is ...........

Answer»

`(0,(PI)/2)`
`(0,pi/4)`
`[(pi)/4 ,pi/2)`
`{pi/4}`

SOLUTION :N/A


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