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f(x) is a polynomial such that f(x)⋅f(1x)=f(x)+f(1x) such that f(3)=28. Then the value of 10∑k=1f(k) is

Answer» f(x) is a polynomial such that f(x)f(1x)=f(x)+f(1x) such that f(3)=28. Then the value of 10k=1f(k) is


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