InterviewSolution
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f(x)=∞∏k=1⎛⎜⎜⎜⎜⎝1+2cos(2x3k)3⎞⎟⎟⎟⎟⎠, then the number of points where [xf(x)]+|xf(x)|+(x−1)|x2−3x+2| is non-differentiable in x∈(0,3π) is equal to (where [.] denotes the greatest integer function) |
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Answer» f(x)=∞∏k=1⎛⎜ ⎜ ⎜ ⎜⎝1+2cos(2x3k)3⎞⎟ ⎟ ⎟ ⎟⎠, then the number of points where [xf(x)]+|xf(x)|+(x−1)|x2−3x+2| is non-differentiable in x∈(0,3π) is equal to (where [.] denotes the greatest integer function) |
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