`f(x)=log_(x^(2)) 25 and g(x)=log_(x)5.` Then f(x)=g(x) holds for x be – InterviewSolution

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1.	`f(x)=log_(x^(2)) 25 and g(x)=log_(x)5.` Then f(x)=g(x) holds for x belonging toA. RB. `{x:0 lt x lt oo, xne 1}`C. `phi`D. None of these
Answer» Correct Answer - B We have `f(x)=log_(x^(2)) 25=log_(x^(2)) 5^(2)=(2)/(2)log_(x)5=log_(x)5=g(x)` for all x in their common domain. Now, `D_(1)="Domain of f"=R-{0,-1,1}` `and D_(2)="Domain of g"={x:x gt 0, x ne 1}` `therefore D_(1) nn D_(2)={x:x gt 0, x ne 1}` `"Thus", f(x)=g(x)"for all" x in {x:x gt 0, xne1}`

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