1.

f(x) = max { sin x, cos x,1/2}the areaof theregionboundedby thecurvey=f(x), X-axisY-axisandx=2piis……..Sq. units

Answer»

`((5PI)/(12)+3)`
`((5pi)/(12)+sqrt(2))`
`((5pi)/(12) + sqrt(3))`
`((5pi)/(12) + sqrt(2) + sqrt(3))`

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