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f(x) = (x+1)3(x - 3)3 is increasing inA. (-∞, 1)B. (-1, 3)C. (3, ∞)D. (1, ∞) |
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Answer» Answer is : D. (1, ∞) Given: ⇒ f(x) = (x+1)3.(x - 3)3 ⇒ f’(x) = 3(x+1)2(x - 3)3 + 3(x - 3)3 (x+1)3 Put f’(x) = 0 ⇒ 3(x+1)2(x - 3)3 = -3(x - 3)2(x+1)3 ⇒ x - 3 = -(x+1) ⇒ 2x = 2 ⇒ x = 1 When x>1 the function is increasing. x<1 function is decreasing. So, f(x) is increasing in (1, ∞). |
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