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f(x) = xx is decreasing in the intervalA. (0, e)B. (0, 1/e)C. (0,1)D. none of these |
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Answer» Answer is : B. (0, 1/e) Given: f(x) = xx . ⇒ f'(x) = (log x+1) xx ⇒ keeping f’(x) = 0 We get ⇒ x = 0 or x = 1/e Now When x > 1/e the function is increasing x < 0 function is increasing. But in the interval (0,1/e) the function is decreasing. |
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