Factories:i. 16a2 – 24abii. 15ab2 – 20a2biii. 12x2y3 – 21x3y2

1.	Factories:i. 16a2 – 24abii. 15ab2 – 20a2biii. 12x2y3 – 21x3y2
Answer» (i) Let’s take HCF of 16a² – 24ab Taking 8a as common from the whole, we get, 16a² – 24ab = 8a(2a – 3b). (ii) 15ab² – 20a²b, Taking 5ab as common from the whole, we get, 15ab² – 20a²b = 5ab(3b – 4a) (iii) 12x²y³ – 21x³y², Taking 3x²y² as common from the whole, we get, 12x²y³ – 21x³y² = 3x²y²(4y – 7x)

Answer»

(i) Let’s take HCF of 16a² – 24ab

Taking 8a as common from the whole, we get,

16a² – 24ab = 8a(2a – 3b).

(ii) 15ab² – 20a²b,

Taking 5ab as common from the whole, we get,

15ab² – 20a²b = 5ab(3b – 4a)

(iii) 12x²y³ – 21x³y²,

Taking 3x²y² as common from the whole, we get,

12x²y³ – 21x³y² = 3x²y²(4y – 7x)

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