Factorise 2) x^3 - 3x^2 - 9x - 5

1.	Factorise 2) x^3 - 3x^2 - 9x - 5
Answer» First we find all the factors of the constant term in the polynomial which is 5 here,All factors of 5 are ±1,±5.Then by Remainder theorem we find that x-5 is a factor of p(x).On dividing p(x) by x-5 we get a quotient q(x) = x^2-2x+1.On factorising q(x) we get other two factors (x-1)(x-1).So all the factors of p(x) are (x-5),(x-1) and (x-1).

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